2z(z+4)=2z^2+8z-8

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Solution for 2z(z+4)=2z^2+8z-8 equation:


Simplifying
2z(z + 4) = 2z2 + 8z + -8

Reorder the terms:
2z(4 + z) = 2z2 + 8z + -8
(4 * 2z + z * 2z) = 2z2 + 8z + -8
(8z + 2z2) = 2z2 + 8z + -8

Reorder the terms:
8z + 2z2 = -8 + 8z + 2z2

Add '-8z' to each side of the equation.
8z + -8z + 2z2 = -8 + 8z + -8z + 2z2

Combine like terms: 8z + -8z = 0
0 + 2z2 = -8 + 8z + -8z + 2z2
2z2 = -8 + 8z + -8z + 2z2

Combine like terms: 8z + -8z = 0
2z2 = -8 + 0 + 2z2
2z2 = -8 + 2z2

Add '-2z2' to each side of the equation.
2z2 + -2z2 = -8 + 2z2 + -2z2

Combine like terms: 2z2 + -2z2 = 0
0 = -8 + 2z2 + -2z2

Combine like terms: 2z2 + -2z2 = 0
0 = -8 + 0
0 = -8

Solving
0 = -8

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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